The width of a rectangle is 33 centimeters. the perimeter is atleast 776 centimeters. write and solve an inequality to find the possible lengths of the rectangle

2(33) + 2ℓ ≥ 776; ℓ ≥ 355; A ≥ 33(355)

Step-by-step explanation:

because

2times 33 is 66

776-66 is 710

710 divided bye 2 is 335

and area is A≥33(355) because area of rectangle is A=33(355)

Plus I just got it right on my quiz.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6