Three consecutive even integers add to −6. what are these integers?

Let's consider the smallest even integer = x.

then second even integer = (x + 2).

and third even integer = (x + 4).

So three consecutive even integers would be x, (x + 2), and (x + 4).

The sum of these numbers is -6. Its equation would be as follows :-

x + (x + 2) + (x + 4) = -6

3x + 6 = -6

3x = -6 - 6

3x = -12

x = -4

So first number = x = -4

second number = (x + 2) = -2

third number = (x + 4) = 0

Hence, three consecutive even integers are -4, -2, and 0

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

sine

step-by-step explanation: