What is the value of the leading coefficient a if the polynomial function p(x) = a(x + b)2(x − c) has multiplicity of 2 at the point (−3, 0) and also passes through the points (2, 0) and (0, 36)? answers: −2−3336

The polynomial is of the form:



We are provided with the two zeros in the question statement. The zero with multiplicity 2 is -3, and zero with multiplicity 1 is 2. So using these values, the polynomial becomes:



The polynomial also passes from the point (0,36). This mean if we substitute x=0, the answer should be 36.



Thus the value of a for given polynomial will be -2. The complete equation of polynomial will be: