The radioisotope cobalt-60 is used in cancer therapy. the half-life isotope is 5.27 years. which is equation determines the percent of an initial isotope remaining after t years?

Answer : The equation determines the percent of an initial isotope remaining after t years is,

Explanation :

Half-life = 5.27 years

Formula used :

       ............(1)

where,

a = amount of reactant left after n-half lives

= Initial amount of the reactant

n = number of half lives

And as we know that,

       ..........(2)

where,

t = time

= half-life  = 5.27 years

Now equating the value of 'n' from (2) to (1), we get:

      ...........(3)

Therefore, the equation determines the percent of an initial isotope remaining after t years is,

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

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step-by-step explanation: