What are the approximate solutions of 2x^2-x+10=0? f) -2,2.5 g) -1.97,2.47 h)-2.5,2 i) no solution. me . : *

To solve this problem, Uuse the quadratic equation:  
(-b +/- sqrt(b^2 - 4ac))/2a, 
 where 
 a = 2
 b = -1
 c = 10 
 Solve: 
 (1 +/- sqrt(1 + 4*2*10))/4 
 (1 +/- 9)/4 
 The two solutions are  
 10/4 = 2.5
 (1-9)/4 = -2. The correct answer is f.

The correct graph is the second one, with the points being at (-6,0), (2,0) and reaching down to (-2,-8)