Me figure this out because everything i've tried doesn't work. i need to finish this to graduateme! a perpendicular bisector, cd , is drawn through point c on ab. if the coordinates of point a are (-3, 2) and the coordinates of point b are (7, 6), the x-intercept of cd is . point lies on cd. part 1 options (3,0) (18/5,0) (9,0) (45/2,0) part 2 options (-52,141) (-20,57) (32,-71) (54,-128)

1. (18/5,0)
First let us find the equation of AB. It should be in the form of y=mx + b
From the given coordinates, you can get m, x, and b.

m= y2-y1 divided by x2 - x1
m=(6-2)/(7- -3)= 4/10 or 2/5
m= 2/5

b is your y intercept
To get it, use 1 coordinate either from point A or B.
Let point A be the coordinates
y=mx + b
-3= 2/5(2) + b
b= - 3- 4/5
b= 16/5

Now we will find the equation of CD,
y=mx + b
y= (-5/2)x + b
Then get the coordinates of point C through midpoint equation,
(x1+x2) /2, (y1+y2) /2
(-3+7)/2, (2+6)/2
=C(2,4)
We will use this coordinates to find b,
y=mx+b
4=(-5/2)2+b
4+5=b
b=9
If we are finding the x intercept, y value should be 0.
0=(-5/2)x+9
0-9(2)/-5=x
x= 18/5
The x intercept of CD is (18/5,0)

2. The answer is (54,-128)

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