Arectangle sand box has a length of 5 1/3 feet and a width of 3 3/4 feet . what is the perimeter

Perimeter is 18 1/6 feet.

Perimeter is solved by adding the length and width of the rectangle and multiplying the sum by 2.

P = 2(l + w)

length = 5 1/3 ⇒ (5*3)+1/3 = 16/3
width = 3 3/4 ⇒ (3*4)+3/4 = 15/4

In adding fractions, make sure that the denominators are the same. Both 3 and 4 are factors of 12. So, we need to multiply each fraction to get 12.

16/3 * 4/4 = 64/12
15/4 * 3/3 = 45/12

Length + Width = 64/12 + 45/12 = (64+45)/12 = 109/12 

P = 2 * 109/12
P = 218/12
P = 18 2/12 ⇒ 18 1/6 feet

Letter a i would say