Arope is sq rt. 250 units long. if cut into 2 pieces so that the lengths of the pieces are in the ratio of 3: 2 what is the length of longer piecein simplest radical form? 3: 2 =5/ do i set x/sq. rt.250=5/3? i end up with 25 sq rt. 10/3. this isn't correct.

Let 3x = the length of the first rope

       2x = the length of the second rope

This representation is based on the given that the ratio of the two ropes is 3:2.

3x + 2x = sq rt. 250

5x = sq rt. 250

x = sq rt. 250 / 5

x = sq rt. 25(10) / 5

x = 5 sq rt. 10 /5

The five would be cancelled resulting to:

x =sq rt. 10

all of them.

step-by-step explanation:

every month has 28 days. some just continue on after reaching 28.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3