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Mathematics, 30.07.2019 06:00 ToriChristine

1. the center of a circle is located at (5, −5) . the radius of the circle is 3. what is the equation of the circle in general form? x^2+y^2+10x−10y+47=0 x^2+y^2+10x−10y+41=0 x^2+y^2−10x+10y+47=0 x^2+y^2−10x+10y+41=0 2.the standard form of the equation of a circle is (x−5)2+(y−6)2=1. what is the general form of the equation? x^2+y^2−10x−12y−62=0 x^2+y^2+10x+12y+62=0 x^2+y^2−10x−12y+60=0 x^2+y^2+10x+12y+60=0

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1. the center of a circle is located at (5, −5) . the radius of the circle is 3. what is the equatio...
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