Which is the standard form of the equation of the parabola that has a vertex of (–4, –6) and a directrix of y = 3?

The required equation is .

Step-by-step explanation:

The standard form of the equation of the parabola is

        .... (1)

where, (h, k) is vertex and  y = k - p is directrix.

It is given that vertex of parabola is (–4, –6) and the directrix is y = 3.

On comparing both the sides, we get

Directrix of the parabola is

Put y=3 and k=-6 in the above equation.

Substitute h=-4,p=-9 and k=-6 in equation (1).

Therefore the required equation is .

the answer is 99.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w