He circle shown below has ab and bc as its tangents: ab and bc are two tangents to a circle which intersect outside the circle at a point b. if the measure of arc ac is 160°, what is the measure of angle abc? (1 point) 80° 40° 60° 20°

m∠ABC=20°

Step-by-step explanation:

Consider quadrilateral ABCO. The sum of the measures of all interior angles in quadrilateral ABCO is equal to 360°.

Lines BA and BC are tangent to the circle, then the radii OC and OA are perpendicular to the tangent lines BC and BA. Therefore,

The measure of the angle AOC is 160° (because the measure of arc AC is 160°). So,

m∠ABC+m∠BCO+m∠BAO+m∠AOC=360°,

m∠ABC=360°-(m∠BCO+m∠BAO+m∠AOC)=360°-(90°+90°+160°)=20°.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: