Mathematics, 30.07.2019 14:00 Andychulo7809
Find the exact length of the curve. x = y48 + 14y2, 1 ≤ y ≤ 2
Answers: 1
![L=\int_1^2\sqrt{(\frac{1}{2}y^3+\frac{1}{2}y^{-3})^2}dy=\int_1^2\frac{1}{2}y^3+\frac{1}{2}y^{-3}dy\\=[\frac{1}{8}y^4-\frac{1}{4}y^{-2}]_2^1\\ =\frac{33}{16}](/tpl/images/0150/7252/64f7a.png)
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Find the exact length of the curve. x = y48 + 14y2, 1 ≤ y ≤ 2...
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