What are the three consecutive odd integers that equal 111? after that, answer this: are there 3 consecutive odd integers that equal ?

Odd integers are 1 more than even ones
even intergers are represetned as 2n where n is a whole number
odd=2n+1
consecutive odd integers are 2 apart from each other so therefor the numbers are 2n+1,2n+1+2, 2n+1+2+2 or 2n+1, 2n+3, 2n+5
so they add up to 111
2n+1+2n+3+2n+5=111
add like terms
6n+9=111
subtract 9 from both sides
6n=102
divide both sides by 6
n=17
numbers are
2n+1,2n+3,2n+5
subsitute
2(17)+1=34+1=35
therefor since the other sare 2 more
35,37,39 are the numbers

are there 3 that equal 1111? solve and see if it is true
2n+1+2n+3+2n+5=1111
add like terms
6n+9=1111
subtract 9 from both sides
6n=1102
divide both sides by 6
n=183.666666666666
n is not whole so the answer is NO

answer are 35,37,39 and NO

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67