Use the law of cosnes. solve each triangle. round your answer to the nearest tenth.

i have 4 problems to solve but i just can't figure these two out.

The law of Cosines states as follows:

where a is the side opposite angle A, b is the side opposite angle B, and c is the side opposite angle C
for problem 1), we can switch it to:


Now you can use the law of sines for a 2nd angle:

and for the 3rd just use the 180-triangle rule:
C = 180 - 40.08 - 87 = 52.92

Now for problem 2)
again, the Law of Cosines, but now we'll switch it to solve for C:

Now for a 2nd angle use the Law of Sines:


finally, use the 180-triangle rule to find B:
B = 180 - 79.36 - 56.33 = 44.31

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.