What is the area of a sector with a central angle of 10π/7 radians and a radius of 18.4 m? use 3.14 for π and round your final answer to the nearest hundredth. enter your answer as a decimal in the box.

Area of sector= \frac{\Theta}{360}\times \Pi \times r^{2}

Area =\frac{10\Pi }{7 }\times \frac{1}{360}\times \Pi \times (18.4)^{2}

Area = \frac{1800 }{7 }\times \frac{1}{360}\times (3.14) \times (18.4)^{2}

So, Area of the given sector= 759.34 square meters.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it