Asimple random sample of 50 adults was surveyed, and it was found that the mean amount of time that they spend surfing the internet per day is 54.2 minutes, with a standard deviation of 14.0 minutes. what is the 99% confidence interval (z-score = 2.58) for the number of minutes that an adult spends surfing the internet per day?

We have that the z-score is defined as z= where X is the value of the observation, m is the mean of all the observations and sigma is the standard deviation. We also have that the z-score of the ends of the confidence intervals is 2.58 and -2.58. We have then, solving the first equation that :
Substituting the values for z, m and sigma, we have that the upper bound of the confidence interval is 90.32 minutes and that the lower bound is 18.08 minutes. Hence, almost all adults (99%) have a total time of watching TV in this interval.

It would be around 260 feet

Istg idk..if there all the same length there all the same number but use google