Plzz find all the 2-digit numbers each of which has n divisors for a)n=8 b)n=9

We need to find 2 digit numbers (10-99) each of which has 
a) 8 divisors
b) 9 divisors
 
Here's what I found:
For 8 divisors, the number must have
    a. 3 distinct prime factors, or
    b. of the form {p^3, q}
    which are:
2^3*3=24 (1,2,3,4,6,8,12,24)
2*3*5=30 (1,2,3,5,6,10,15,30)
2^3*5=40 (1,2,4,5,8,10,20,40)
2*3*7=42 (1,2,3,6,7,14,21,42)
2*3^3=54 (1,2,3,6,9,18,27,54)
2^3*7=56 (1,2,4,7,8,14,28,56)
2*3*11=66 (1,2,3,6,11,22,33,66)
2^3*11=88 (1,2,4,8,11,22,44,88)
2*3*13=78 (1,2,3,6,13,26,39,78)
2*5*7=70 (1,2,5,7,10,14,35,70)

For 9 divisors, it is necessary that the 2-digit number be a perfect square, and the square-root is composite.
For this, we can list only
(2*3)^2=36  (1,2,3,4,6,9,12,18,36)

So there are 10 2-digit numbers with 8 factors, and 1 with 9 factors.

Note: looks like 72 has 12, the most factors in two digit numbers:
72 (1,2,3,4,6.8,9,12,18,24,36,72)

Hmm i believe it would be c

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle