Sebuah prisma dengan alas berbentuk belah ketupat mempunyai panjang diagonal 24 cm dan 10 cm. jika tinggi prisma 8 cm , maka luas permukaan prisma adalah

The question in English is
A prism with a rhombus pedestal has a diagonal length of 24 cm and 10 cm. if the height of the prism is 8 cm, then the surface area of the prism is

we know that
h=8 cm
D=24 cm
d=10 cm
Area of the rhombus=(d*D)/2=10*24/2=120 cm²
now calculate the side of the rhombus with Pythagorean theorem
L=√(d/2)²+(D/2)²=√(10/2)²+(24/2)²=13 cm
surface area of the prism=[120*2+13*8*4]=656 cm²

the answer is 656 cm²

the answer in Malay

kami tahu itu
h=8 cm
D=24 cm
d=10 cm
Kawasan rombus=(d*D)/2=10*24/2=120 cm²
kini mengira sisi rombus dengan teorem Pythagoras
L=√(d/2)²+(D/2)²=√(10/2)²+(24/2)²=13 cm
kawasan permukaan prisma=[120*2+13*8*4]=656 cm²

jawapannya ialah 656 cm²

Dbc if u do the math and stuff that what i got let me know if i was wrong