Find two consecutive odd integers such that 36 more than the lesser is three times the greater

Two consecutive odd integers means there's a difference of 2 between the numbers. More than the lesser is adding to the lower integer (x). The greater is the larger integer (x+2). "Is" means equals. Times means multiply.

x= first integer
x+2= second integer

x + 36= 3(x + 2)
multiply 3 by everything in parentheses
x + 36= 3x + 6
subtract x from both sides
36= 2x + 6
subtract 6 from both sides
30= 2x
divide both sides by 2
15= x

x= 15 first consecutive odd integer

x+2= second consecutive odd integer
15+2= 17

ANSWER: 15, 17

Hope this helps! :)