Aspinner has 14 equal sectors with different letters for each sector, as shown below: a spinner with 14 equal sectors is shown. the sectors are labeled b, y, g, c, p, f, o, v, m, a, d, e, h, and r. victoria spins the spinner 18 times, and it stops at the letter b 10 times. if she spins the spinner a 19th time, what is the theoretical probability that this time it will stop at the letter b? 1 over 20 1 over 18 1 over 14 1 over 10

1 over 14

Step-by-step explanation:

The sectors labeled are B, Y, G, C, P, F, O, V, M, A, D, E, H, and R.

Total number of sectors = 14.

When Victoria spins the spinner 18 times, and it stops at the letter B 10 times.

When Victoria spins the spinner  the theoretical probability that this time it will stop at the letter B = Favourable  outcomes ÷total numner of outcomes.

Favourable outcomes =1 and Total number of outcomes = 14.

Hence Theoritical Probability = 1 over 14.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for