What is the slope of any line perpendicular to y=-1/3x+22

The slope of any line perpendicular to the given line is 3

Explanation:
The general form of the linear line is:
y = mx + c where m is the slope
The given line is:
y = -1/3 x + 22
Comparing the given line with the general form, we will find that:
slope of the given line (m1) is -1/3

Now, for any two lines to be perpendicular, the product of their slopes should be equal to -1.
This means that:
m1 * m2 = -1
We have m1 = -1/3
Therefore:
-1/3 * m2 = -1
m2 = 3*1
m2 = 3

Hope this helps :)