The y-intercept for the function ƒ(x) = is (0, -4) true false

Since you did not include the function f(x), I wll explain you what the y-intercept is and how to find it.

1) The y-intercept is the value of the function, for x = 0.

2) So, to find the y-intercept when you have the function, you need to solve the equation for y when x = 0.

For example if the fucntion is y = f(x) = x^2 + 5, the y-intercept is y = f(0) = 0^2 + 5 = 5.

3) Graphically, the y-intercept is the point where the graph of f(x) crosses the y-axis.

So, if you have the graph, you just read the value of the function on the y-axis.

Taking all that information, you do not report the y-intercept as a pair of coordinates. The y-intercept is reported just as a value for y.

For example, assuming that the point (0, - 4) you do not say that the y-intecept is (0,-4), you say that the y-intecept is -4, because that is the value of the function when x = 0.

Using the explanation from the previous paragraph, you should say FALSE, because the y - intercept is only the y-value when x = 0.

FALSE.

The distance from point a to point c across the coordinate plane is aproxamatly 8.94 rounded to the nearest hundredth. you use a^2 + b^2 =c^2

It is e) i am not sure if you have any questions or need any