When water freezes, its volume increases by 1/11 . while melting, by what fraction does the volume of ice change?

The volume of ice changes by 1/12

Explanation

Lets assume the volume of the water is V

When water freezes, its volume increases by 1/11 . So, the new volume of the ice

When the ice is melting, it returns to its original volume V. So, the volume decreased while melting

This time the volume has decreased from a starting point of

So, the fraction of change will be :

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

answer: i think one of the answer is $150 and $300?

step-by-step explanation: