Use the numbers from the original example: $1,000 invested at a 2% interest rate compounded n times per year. compare the change in p as n increases. fill in the table. use a calculator and write the values to 5 decimal places. n 1.) 1 (once per year) 2.) 4 (every 3 months) 3.) 12 (every month) 4.) 52 (every week) 5.) 365 (every day) p=po(1+ r/n) is the equation used [o=0 placed at the bottom of the p]will mark as

Given:
P₀ = $1000, the principal
r = 2% = 0.02, the APR

Let the duration be 1 year 
n =  number of compounding intervals per year.
The value after 1 year is


The following table shows the results obtained from the calculator.

     n                   A
------  ------------------
     1   1020.00000
     4   1020.15050
    12   1020.18436
    52  1020.19742
  365  1020.20078

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.