Find four consecutive integers whose sum is 290. 1 point: for writing out the equation that you are solving. 1 point for all 4 consecutive integers.

For an instance, n is the smallest number, then the other number will be (n + 1), (n + 2), (n + 3)

Write an equation based on the problem
the sum of the numbers = 290
n + n + 1 + n + 2 + n + 3 = 290
4n + 6 = 290
This is the equation

Solve the equation
4n + 6 = 290
4n = 290 - 6
4n = 284
  n = 284/4
  n = 71
The smallest number is 71

Find the other three numbers
n + 1 = 71 + 1 = 72
n + 2 = 71 + 2 = 73
n + 3 = 71 + 3 = 74
The other numbers area 72,73,74