Best explained and correct answer gets

So our line is: y = 6x + 7

Step-by-step explanation:

Now, we need to find which equation of a line that has a y-intercept of 7 and is parallel to the line: y = 6x -5

So, if that equation is is parallel to the line: y = 6x -5 , so it has a standard from

(Because, if 2 lines are parallel with each other, they will have the same slope)

And it has a y-intercept of 7 when x = 0, so we have:

y = 6x+ m

<=> 7 = 6*0+m

<=> m = 7

So our line is: y = 6x + 7

We choose A

Hope it will find you well.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°