Arectangular pool has dimensions of 40 ft. and 60 ft. the pool has a patio area around it that is the same width on all sides. if the patio area equals the area of the pool, how wide is the distance from the pool edge to the patio edge?

Let

x> the width of the patio

we understand that

region of the pool=40*60> 2400 ft²

vicinity of the patio=[(40+2x)*(60+2x)]-2400

place of the patio=2400 ft²

so

[(40+2x)*(60+2x)]-2400=2400

2400+80x+120x+4x²-4800=0

4x²+200x-2400=0> divide by 4 both sides> x²+50x-600=0

therefore

the answer is

x²+50x-600=0

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.