Acar went 60 km in 5/6 of an hour while a second car went 54 km in 2/3 h. which car was faster? how many times faster? asap plz

This is the relationship between distance, velocity and time
v = d/t

To find which car was faster, we need to find the velocity
First car
d = 60 km
t = 5/6 of an hour

Calculate the velocity of the first car
v = d/t
v = 60 ÷ 5/6
v = 60 × 6/5
v = 72
The velocity of the first car is 72 km/hour

Second car
d = 54 km
t = 2/3 of an hour

Calculate the velocity of the second car
v = d/t
v = 54 ÷ 2/3
v = 54 × 3/2
v = 81
The velocity of the second car is 81 km/hour

81 is bigger than 72. The second car was more faster

81 - 72 = 9 km/hour
The second car was 9 km/hour faster than the first car

You have 2 sides that are 2 cms and you have 6 sides that are 1/2 cm and you have 4 sides that are 1 cm. the smallest sides are 1/2 the medium sized sides are 1 and the smallest are 1/2. so to find the perimeter you have to add them all up together so your answer will be 11 cm's