Write the equation for the line that is perpendicular to given line that passes through the given point -3x-6y=17; (6,3)

Step-by-step explanation:

you have the line

clearing for y:

we have an equation of the form

the number that accompanies the x is the slope, and the number alone is the intercept with the y-axis

the slope m is:

i will call the slope of the new line

so for two perpendiculares lines we must have:

and from this we can find the new slope:

the new slope is 2,

so far we have that the new line is:

so now we have to find the intercept with the y axis () of the new line, since it passes trough (6,3) ---> x = 6 when y = 3

substituting these x and y values in :

and finally, the equation of the new line that is perpendicular to the original line is:

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.