At 2pm the level of the water in the pool was 10feet. at 6pm the level of water was 2 feet. what is the constant rate

2 pm to 6pm is 4 hours

10 feet - 2 feet = 8 feet

 8 feet / 4 hours = 2 feet per hour

 since it is losing water it would be negative 2 feet per hour

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.