What is the least common denominator of the fraction 4 over x plus the fraction 2 x over x minus 1 plus the fraction x plus 3 over 2 x

1. which answer is the solution set to the given inequality? 2x+6< 8 a. x e (-∞,1) b. x e [1,∞) c. x e (1,∞) d. x e (-∞,1] 2. which answer represents the given compound inequality in interval notation? x≥12 or x< -4 a. x e [-4, 12) b. x e (-∞, -4) u [12,∞) c. x e (-∞, -4] u (12,∞) d. x e (-4,12] 3. which answer is the solution set of the given compound inequality? 7> x+6 or x-2≥3 a. x e (-∞, 1) u [5,∞) b. x e (1, 5] c. x e (-∞, 1) ∩ [5,∞) d. x e [1,5) 4. which conjunction or disconjunction is equivalent to the given absolute value inequality? |x+3|> 12 a. x+3> 12 and x+3< -12 b. x+3< 12 and x+3> -12 c. x+3< 12 or x+3> -12 d. x+3> 12 or x+3< -12