The sum of 5 consecutive odd numbers is 145. what is the third number in this sequence?

The answer is 29 

let n be the first of the consecutive odd numbers
⇒ n, n+2, n+4 n+6, n+5
represent 5 consecutive odd numbers
sum = n+ (n+2) + (n+4) + (n+6) + (n+8) = 5n+20
⇒ 5n +20=145 
Solve for n = 25

25, 27, 29, 31, 33

25+27+29+31+33=145