What is the area of a regular octagon with a side of 8 in. round to the nearest tenth, show work

Length of each side of a regular octagon = 8 inches
We already know the formula for finding the area of a regular octagon as
Area = 2 (1 + square root 2) * (Side)^2
         = 2 (1 + 1.414) * (8)^2
         = 2 (2.414) * 64
         = 308.99 inches ^2
         = 309 inches ^2
So the area of the regular octagon having sides of 8 inches is 309 square inches. This is the easiest method for solving these kind of problems.

W-14=t. that i think is the answer idk