Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 6.   log base 2 graph 

F(x) = log2x- -------> y=log2x-------- > 2^(y)=x  (I)

therefore

in the equation  2^(2y) = 6---- >(2^(y))^2 = 6  (II)

(I) in (II)

((x))^2 = 6-----------------x=2.45

using a graphic tool
see graphic attached

for x=2.45 the value of y approximate is 1.2928

Hello sorry can’t good luck tho

Yes you do, so £1973.09 - £1473.50 = £499.59 so tim overpaid £499.59 .hope this ; )