Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now



recall that 



therefore, let's just plug that on the remaining ones,



now, let's rationalize the denominator on tangent and secant,

What are the following algebraic equations. you need to post those if you want the answer

Yuh yeet honestly idk