The axis of symmetry for the function f(x)= -x2 - 10x + 16 is x =-5. what are the coordinates of the vertex of the graph

Vertex will be (-5, 41)

Step-by-step explanation:

For a quadratic function f(x) = ax² + bx + c

If axis of symmetry is x = -5 then coordinates of vertex will be [x, f(x)]

The given f(x) in the question is f(x) = -x² - 10x + 16

and line of symmetry is x = -5

then f(-5) = -(-5)² - 10(-5) + 16

               = -25 + 50 + 16

               = 41

Therefore, Vertex will be (-5, 41)

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph