What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)?

C ) y + 3 = 1/4 ( x + 4 )

Explanation:

Given that you did not include the "given line", I can help you by explaning how to solve this kind of problems, step by step.

The procedure is based of the property of perpendicular lines: the product of the slopes of perpedicular lines is negative 1.

If you call m1, the slope of a line and m2 the slope of a perpendicular line, then:

m1 * m2 = - 1, and you can solve for either m1 or m2:

m1 = - (1 / m2)

m2 = - (1 / m1).

With that this is the procedure:

1) find the slope of the "given line". Name it m1.

2) find the slope of the perpendicular line:

    m2 = - (1 / m1).

3) Use the equation of the line with the point (x1,y1) and slope m2

y - y1
= m2
x - x1

4) In this case the point is (-4, - 3)=> x1 = - 4, y1 = - 3

=>

y - (-3)
= m2
x - (-4)

=> y + 3 = m2 * (x + 4)

=> y = m2*x + m2 * 4 - 3

Which is the point-slope form. You only have to replace m2 with the slope value of the perpendicular line, which I already explained that you find as m2 = (-1/m1).

Taking that the other line has m1 = - 4 so m2 = 1/4

      y = (1/4)x + (1/4) * 4 - 3

      y = (1/4) (x +4) - 3

      y + 3 = (1/4) (x + 4) and answer is: C ) y + 3 = 1/4 ( x + 4 )