Which equation is y=6x^2+12-10 rewritten in vertex form

The formula in order to obtain the vertex form of a quadratic equation is given as 

y=a(x-h)^2+k where (h,k) is the vertex of the quadratic equation which is parabolic in shape and it is opening upward.

As given in the problem, y=6x^2+12x-10

Using the formula, we can transformed the quadratic equation y=6x^2+12x-10 into its vertex form:

y=6x^2+12x-10

y= (6x^2+12x)-10    (grouping)

y=6(x^2+2x)-10 (factoring Common terms per group)

y=6(x^2+2x+1)-10-6 (Completing the squares)

y=6(x+1)^2-16    (Factor and Simplify)

Hence, the vertex form of y=6x^2+12x-10 is y=6(x+1)^2-16

the answer is c hope it

step-by-step explanation: