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Mathematics, 04.12.2019 03:31 trobbie817

Given △abc, sin(a) =

a. cos(b)
b. sin(b)
c. cos(c)
d. tan (c)


Given △abc, sin(a) =  a. cos(b) b. sin(b) c. cos(c) d. tan (c)

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Given △abc, sin(a) =

a. cos(b)
b. sin(b)
c. cos(c)
d. tan (c)
...
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