Achemist has one solution that is 80% acid and another solution that is 30% acid. how much of the first (80%) solution is needed to make a 400 l solution that is 62% acid?

Let x be the quantity of solution one in mixture.
so solution 2 would be (400-x) L

according to ques.
80% of x + 30% of (400-x) = 62% of 400
i.e. 80*x/100 + 30*(400-x)/100= 62*400/100
=> 80x - 30x = 62*400 - 30*400
=> 50x = 32*400
x=256 L
therefore 256L of solution one is required

A’b’c’ are the coordinates to the new location of the transformed triangle abc. find the distance between the coordinates points to use for your calculations.