Find the product of (–d + e)(4e + d). which statements are true? check all that apply. there are 2 terms in the product. there are 3 terms in the product. there are 4 terms in the product. the product is degree 1. the product is degree 2. the product is degree 4.

The product of the given expression is -3ed + 3e^2 showing that they contain two terms and the product has a degree of 2

Equation are expressions separated by an equal sign.

Given the following expression

(–d + e)(4e + d).

We are to take the product of both expressions

Expand to have:

(–d + e)(4e + d) = -4ed - d^2 + 4e^2 + de

(–d + e)(4e + d) = -3ed + 3e^2

From the final answer, you can see that there are two terms in the solution and the product is degree 2

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