The area of a rectangular field is 2c3 − c2 + 6 square units. if the length of the field is c − 2 units, what is its width? the width of the field is units. nextreset

Area of the rectangle can be calculated using the following rule:
Area of rectangle = length * width

We are given that:
area = 2c^3 − c^2 + 6 square units
length = c - 2 units

Substitute with the givens in the above equation and solve for the width as follows:
Area of rectangle = length * width
2c^3 − c^2 + 6 = (c - 2) * width
width = (2c^3 − c^2 + 6) / (c - 2) units

Doing the long division for this one, we will find that the simplest form will be:
width = 2c^2 + 3c + 6 + [18/(c-2)]

Hope this helps :)
Note: The attached image shows the procedures of the long division for this problem :)

It has a slope of 1 nd a y intercept of -2