What is the center of a circle circumscribed about the coordinates a(2,8), b(0,8), c(2,2) i need asap

Ba is a horizontal line. ac is a vertical line.hence angle bac is a right angle.therefore bc is the diameter of the circle.center of circle is the midpoint of bc, which is (1, 5).the radius is half of bc, which is 2sqrt10.therefore the equation is (x-1)^2 + (y-5)^2 = 40

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Uneed to add them up 27+18+23=68