How many times does 8 go into 103? what is the remainder?

WELL IF YOU DIVDE LIKE THIS:
  
                           X
                        8  ) 1 0 3
 8 X ? = 1
 WELL ITS NOT POSSIBLE. SO YOU NEED TO PUT A 0 THAN PASS DOWN TO THE NEXT NUMBER.
     
              X_0_?
              8) 1 0 3
 8 X ? = 10
WELL IF 8 X 1 = 8 THEN 8 X 2 = 16 
YOUR ANSWER WILL BE 1. 
  

             X_0_1
              8) 1 0 3
               -     8  I 
              \/
                      2 3
8 X ? = 23
 IF 2 X 8 =16 THEN YOU GET 2
    
       X 0_1_2_R_7
      8) 1 0 3
        -     8 I
     \/
              2  3
       -       1 6
      
                 0  7
07 IS THE REMAINDER SO YOU ANSWER IS 12 R 7.