Three dice are tossed, one red, one blue, and one green. what outcomes make up the event a that the sum of the three faces showing equal 5

The outcome that makes up the event a that the sum of the three faces showing equal 5 is; P(E) = 1/36

Since there are three dices.

Let Red dice be R

Let Blue dice be B

Let Green Dice be G

      Now, for the sum of the three numbers on all dice to equal five, it means that no number out of the six possible numbers must be greater than 3.

Thus, P(R) = 3/6

Now, if P(R) = 3/6, it means that none of the other 2 dice can produce 3 or more as it will make the sum more than the required 5.

Thus; P(B) = 2/6

Now, if we now have P(R) and P(B) is gotten, it means P(Y) must be 1/6

Thus, the outcome that makes up the event a that the sum of the three faces showing equal 5 is P(E) = 3/6 × 2/6 × 1/6

P(E) = 1/36

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