Which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2?

f(x) :4x² -7x + 10.

Step-by-step explanation:

Given  : function f(x) has a lead coefficient of 4 and roots 5 and 2.

To find : Which second-degree polynomial function f(x) .

Solution : We have given that f(x) has a lead coefficient of 4 and roots 5 and 2.

Root are (x -5)(x-2).

on  solving we get ,

x²-2x -5x + 10

x² -7x + 10.

We have given leading coefficient is 4

f(x) :4x² -7x + 10.

Therefore, f(x) :4x² -7x + 10.

step-by-step explanation: