Which of these ordered triples indicates where the plane cuts the x-axis for this equation? 3x + 4y + 6z = 12 (4, 0, 0) (4, 3, 2) (0, 3, 0) (0, 0, 2)

Option A is correct.

Step-by-step explanation:

Given equation is 3x + 4y + 6z = 12

We have to find ordered triplet which indicate where the plane cuts the x-axis.

To find x-coordinate where plane cuts the x-axis we put y and z equal to 0.

3x + 4 × 0 + 6 × 0 = 12

3x + 0 + 0 = 12

3x = 12

x = 4

So, the coordinate where  it cuts x-axis is ( 4 , 0 , 0 )

Therefore, Option A is correct.

over the argument its not good to fight.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?