Abale of hay in the shape of a rectangular prism has a length of 4 feet, a width of 2 feet, and a height of 2 feet. a cylindrical bale of hay has a diameter of 5 feet and a height of 6 feet. how many rectangular bales contain the same amount of hay as one cylindrical bale?

The number of rectangular bales contains the same amount of hay as one cylindrical bale is 7.

Here we have to find the volumes of Bale and cylinder:

For bale, the volume is

For cylinder, the volume is

Now we have to divide each volume to each other  i.e.

= 7

Therefore we can conclude that the number of rectangular bales contains the same amount of hay as one cylindrical bale is 7.

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Find the two volumes separately:

Bale:  V = 4(2)(2) ft^3 = 16 ft^3
Cylinder:  V = pi*(2.5 ft)^2* (6 ft) = 117.8 ft^3

Divide 117.8 ft^3 by 16 ft^3:

117.8 ft^3
= 7.36
 16 ft^3

Thus, the cyl. bale could theoretically hold the total volume of 7.36 rect. bales.  That could be rounded off either way:  to 7 or to 8 bales; 7 is closer and thus is the better answer.

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67

No i refuse to tell you the answer but the estimate is 10