Which of the following show the factor equivalent to f(x)=(2x^2+7x+3)(x-3)

 2.1     Factoring  2x2+7x+3 

The first term is,  2x2  its coefficient is  2 .
The middle term is,  +7x  its coefficient is  7 .
The last term, "the constant", is  +3 

Step-1 : Multiply the coefficient of the first term by the constant   2 • 3 = 6 

Step-2 : Find two factors of  6  whose sum equals the coefficient of the middle term, which is   7 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  1  and  6 
                     2x2 + 1x + 6x + 3

Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (2x+1)
              Add up the last 2 terms, pulling out common factors :
                    3 • (2x+1)
Step-5 : Add up the four terms of step 4 :
                    (x+3)  •  (2x+1)
             Which is the desired factorization

here is your mark brainliest

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36