Which of the following ordered pairs could be placed in the table below and still have the relation qualify as a linear function? input (x) output (y) −5 7 −3 15 −1 23 ? ? (0, 31) (−7, 30) (1, 31) (0, −1)

The correct option is 3.

Step-by-step explanation:

If a linear function passing through two point, then the equation of linear function is

From the given table it is clear that the function passing through the points (-5,7), (-3,15) and (-1,23).

Consider any two points from them, i.e., (-3,15) and (-1,23). So, the equation of line is

The equation of line is y=4x+27.

At x=0,

At x=-7,

At x=1,

Only point (1,31) is satisfy the equation of line. Therefore the ordered pairs (1,31) could be placed in the table below and still have the relation qualify as a linear function.

Hence option 3 is correct.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

35%

step-by-step explanation: